Rangkaian Listrik
Rangkaian Listrik
Perhatikan rangkaian listrik dibawah ini:
Tentukan:
a. Arus total?
b. Hambatan dimasing-masing?
c. Hambatan total?
d. Arus dimasing masing?
Jawab :
R345= 200+200+200 R234568 = 200+200+150
= 600Ω = 550Ω
R3458=
+
R2345689 =
+ ![](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABQAAAAcCAMAAABWBG9SAAAAAXNSR0IArs4c6QAAAEhQTFRFAAAAAAAAAABmADo6ADqQAGa2OgAAOgBmOjqQOpDbZgAAZrb/kDoAkDo6kDpmkNv/tmYAtv//25A62////7Zm/9uQ//+2///b6tYd2QAAAAF0Uk5TAEDm2GYAAAAJcEhZcwAADsQAAA7EAZUrDhsAAAAZdEVYdFNvZnR3YXJlAE1pY3Jvc29mdCBPZmZpY2V/7TVxAAAAdklEQVQoU61QSxaAIAiE/qaV+b3/TQNpVStezWJ8jjOAAKiRuvOZKWs/v0SA/L/oEdGoR9YEqMELmvxHb0IcIuQJR9pfYzqXWFZbt6O6m6VJ3U9esTfCIgbLfgijsGj0xp7QnHxrWrJc1t3MjSb6ugWagXLCClygFwY2CeemSwAAAABJRU5ErkJggg==)
= 150Ω = 146,67Ω
Rtotal = 146,67 + 200 + 200
= 546, 67Ω
Itotal=
=
= 0,04 Ω I2 =
=
= 0,012 A
V234568 = Itot. R V345 = I2 . R3458 = 0,01 . 150 = 1,5 V
= 0,04. 146,67 = 5,9 V
I9 =
= 0,03 A I3 =
=
= 0,0025 A
I8 =
=
= 0,0075 A
PEMBUKTIAN MENGGUNAKAN MULTISIM
Reverensi:
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